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求一个C#的 post请求 json 并且接收返回json数据的...

public string HttpPost(string url,string data) { HttpWebRequest request=(HttpWebRequest)WebRequest.Create(url); request.ContentType="application/json"; request.Method="POST"; byte[] buffer=Encoding.UTF8.GetBytes(data); using(St...

Web Service接口方法 [WebMethod] public string Project(string paramaters) { return paramaters; } 实现代码 public string Post(string methodName, string jsonParas) { string strURL = Url + "/" + methodName; //创建一个HTTP请求 HttpW...

你这个应该是两个问题, 1、如何从http返回json 2、如何使用C#读取从http返回的json 解决方案: 问题1:http返回json可以使用webapi技术,自己开发一个webapi接口用于从数据库读取并提供数据。 问题2:首先要说一下,http的json如果是前端程序还...

string postUrl = " HttpWebRequest http; HttpWebResponse response; http =WebRequest.Create(postUrl) as HttpWebRequest; using (response = (HttpWebResponse)http.GetResponse()) { using (StreamReader reader = new StreamReader(respo...

可参考 ArrayList list = new ArrayList(); ArrayList listjson = new ArrayList(); object[] obj; for (int i = 0; i < 120; i++) //获取最新的前120条数据 { string columncontent = 数据; string columntables = 数据; obj = new object[] ...

Web Service接口方法 [WebMethod] public string Project(string paramaters) { return paramaters; } 实现代码 public string Post(string methodName, string jsonParas) { string strURL = Url + "/" + methodName; //创建一个HTTP请求 HttpW...

public static string GetHTTPInfo(string urlPath, string eCode, int millisecond) { string str = null; HttpWebResponse response = null; StreamReader reader = null; try { HttpWebRequest request = (HttpWebRequest)WebRequest.Create(...

HttpWebRequest req = WebRequest.CreateHttp(url);var buffer = Encoding.UTF8.GetBytes(formData);req.Method = "POST";req.ContentType = "application/json";req.ContentLength = buffer.Length;using (var fs = req.GetRequestStream()){ f...

X 表示以十六进制形式输出 02 表示不足两位,前面补0输出;出过两位,不影响 举例: printf("%02X", 0x123); //打印出:123 printf("%02X", 0x1); //打印出:01

http://www.cnblogs.com/lori/p/4045633.html 看里面的dopost这一块

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